What is the 24th term of the arithmetic sequence where a1 = 8 and a9 = 56 ?

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01-09-2017
Mathematics

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What is the 24th term of the arithmetic sequence where a1 = 8 and a9 = 56 ?

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authenticricket authenticricket · Answer 1 · 2017-09-01T10:15:18+02:00

authenticricket authenticricket

01-09-2017

the formula is Tn = a + (n-1)d for arithmetic sequence
where Tn is the term, a is the first term, n is the no. of term, d is the difference
a = 8
Using a9=56,
56 = 8 + (9-1)d
48 = 8d
d = 6
thus, Tn = 8 + (n-1)6
when n=24, Tn = 8 + (24-1)(6) = 146

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nathanielvarol16 nathanielvarol16 · Answer 2 · 2019-07-23T16:24:58+02:00

nathanielvarol16 nathanielvarol16

23-07-2019

Answer:the answer would be c which is 146

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