Answer:
[tex]x=-\frac{3}{2}[/tex]
Step-by-step explanation:
We have been given an equation [tex]\frac{1}{4}+\frac{1}{2}+x=-\frac{3}{4}[/tex]. We are asked to solve for x.
Let us make common denominator as:
[tex]\frac{1}{4}+\frac{1*2}{2*2}+x=-\frac{3}{4}[/tex]
[tex]\frac{1}{4}+\frac{2}{4}+x=-\frac{3}{4}[/tex]
Add numerators:
[tex]\frac{1+2}{4}+x=-\frac{3}{4}[/tex]
[tex]\frac{3}{4}+x=-\frac{3}{4}[/tex]
[tex]\frac{3}{4}-\frac{3}{4}+x=-\frac{3}{4}-\frac{3}{4}[/tex]
[tex]x=\frac{-3-3}{4}[/tex]
[tex]x=\frac{-6}{4}[/tex]
[tex]x=-\frac{3}{2}[/tex]
Therefore, the value of x is [tex]-\frac{3}{2}[/tex].