ximenafex ximenafex
  • 02-12-2016
  • Mathematics
contestada

How do you solve logarithmic equations such as log(2x)= -1 or 3log(2)+log(x)= 3?

Respuesta :

apologiabiology
apologiabiology apologiabiology
  • 02-12-2016
remember some simle log rules
loga+logb=log(ab)
xloga=loga^x
[tex]log_ax=y[/tex] means [tex]a^y=x[/tex]
also, if no base is stated, assume base 10

so

log(2x)=-1 is base 10 and translates to
10^-1=2x
1/10=2x
divide both sides by 2 aka times 1/2
1/20=x



3log(2)+log(x)=3
log(2^3)+log(x)=3
log(8)+log(x)=3
log(8x)=3
base 10
10^3=8x
1000=8x
divide both sides by 8
x=125
Answer Link

Otras preguntas

How many flags are in this wolld ;)
in the xy-plane above, point c has coordinates (6,9). which of the follwoing is an equation of the line that contains points 0 and c?
How is 3x-y=8 and x+2y=5 solved by combination (addition)?????
simplify (1/x) + (1/(x+h)
How is 3x-y=8 and x+2y=5 solved by combination (addition)?????
where did japan first expand its empire after 1930
Add these fractions (Lowest Terms) a) 1/6 + 1/6 b) 1/4 + 3/8 c) 2/3 + 5/6 d) 9/21 + 4/7 e) 1 3/5 + 1/10 f) 1 1/4 + 11/12 g) 1 2/3 + 2/3 h) 1 5/6 + 3 2/5
simplify (1/x) + (1/(x+h)
A particle travels in a circle of radius 82 cm and with a centripetal acceleration of 4.7 m/s2. How long does the particle take to complete one revolution?
the graph below shows the distribution of students grades on their last math test. Based on the Empirical rule, what percent of students made.. *btwn 80 n 85 o