antoinestill41 antoinestill41
  • 01-05-2020
  • Physics
contestada

An object moving at a velocity of 32m/s slows to a stop in 4 seconds. What was its acceleration?

Respuesta :

VirgoBoy VirgoBoy
  • 01-05-2020

Answer:

8m/s

Explanation:

a=d/t

a=32/4

a=8 m/s

Answer Link
Chelboy
Chelboy Chelboy
  • 01-05-2020

Answer:

-8m/s^2

Explanation:

initial velocity(u)=32m/s

Final velocity(v)=0

Time(t)=4seconds

Acceleration(a)=?

v=u+axt

0=32+ax4

-32=4a

a=-32/4

a=-8m/s^2

Answer Link

Otras preguntas

Black codes were established in the south immediately after the civil war in an effort to
What were gerald ford’s greatest successes as president?
rewrite the expression using distributive property: 12x+18
What does the judicial branch consist of??
IS ANY BODY GOOD AT MATH
PLEASE I NEED THE CORRECT ANSWER !!!
The area of a semicircle is 2 times the area of a circle. True False
find 2% of 23 . Do not round your answer.
The area of a semicircle is 2 times the area of a circle. True False
Write a paragraph proof.Given: Vertical isosceles triangles. RS bisects QT. prove: ΔQRP≈ΔTSP