0001 0000 1100 0011 (unsigned, that is, interpreted as b2u)i.8 bit truncated value:ii.does the value change when truncated to 8 bits?iii.how did you decide?d.1101 1111 0011 1010 (signed, that is, interpreted as b2t)i.8 bit truncated value:ii.does the value change when truncated to 8 bits?iii.how did you decide?
I don't know what b2u and b2t are but I'll manage.
0001 0000 1100 0011 unsigned
i. We'll assume when we' truncate we get the low order bits:
1100 0011 unsigned
ii. Those are different
iii. There's a 1 in the high order bits that got thrown away when we truncated.
1101 1111 0011 1010 signed
i. Truncated:
0011 1010
Typically when we'd coerce a signed twos complement value to eight bits we'd preserve the sign. Calling it truncation makes it sound to me that wasn't intended.
